"SPHERICAL REFRACTING SURFACES, IMAGE FOCAL LENGTH. A diagram of the Problem is shown below. Surface is represented by 's'. s ∞<· · · · · · · · ·o·A F = object focus N[1] = index L[O] s · · L[I] V = vertex of sphere outside s R· · S = object at ∞ N[2] = index o· · · o · · ·o L[O] = ∞ inside V|s C F L[I] = distance from A to image N[1] | s N[2] | F[O] = ∞ | s | F[I] = image focal length ∞<---F[O]------|------F[I]---| C = center of sphere R = radius curvat. (c) Copyright PCSCC, Inc., 1993 Sign Convention: F[O] = ∞ F[I] + means image is right of vertex V R + means center C is right of V *** Answer(s) to problem *** Variables are set to proper values at entry. Note, value of unknown should be set to 0.0. Enter any 3 of 4 knowns, program calculates missing (=0) one. F[I] = 19.6. Image is real and to right of V. Type any key to exit. ||An interface separates air on the left and glass (Ng=1.44) on the right. (a) What is the image focal length if its radius of curvature is 6 cm? Type comma key to see answer. Type (F2) to return to application file."
